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The diode shown in the circuit is a silicon diode. The potential difference between the points A and B will be A. 0.7v B. 0.6V D. 6 V C.OV |
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Answer» In the given condition DIODE is in reverse BIASING so it acts as open CIRCUIT. HENCE potential difference between A and B is 6V. option C 6 V is correct please mark me brain mark list |
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