1.

The diode shown in the circuit is a silicon diode. The potential difference between the points A and B will be A. 0.7v B. 0.6V D. 6 V C.OV​

Answer»

In the given condition DIODE is in reverse BIASING so it acts as open CIRCUIT. HENCE potential difference between A and B is 6V.

option C 6 V is correct

please mark me brain mark list



Discussion

No Comment Found

Related InterviewSolutions