The displacement of a particle is moving by `x = (t - 2)^2` where `x` is in metres and `t` in second. The distance covered by the particle in first `4` seconds is.A. 4mB. 8mC. 12 mD. 16 m

The displacement of a particle is moving by `x = (t - 2)^2` where `x`

1.	The displacement of a particle is moving by `x = (t - 2)^2` where `x` is in metres and `t` in second. The distance covered by the particle in first `4` seconds is.A. 4mB. 8mC. 12 mD. 16 m
Answer» Correct Answer - B Given `x=(t-2)^(2)` velocity, `v=(dx)/(dt)=(d)/(dt)(t-2)^(2)=2(t-2)m//s` Acceleration `a=(dv)/(dt)=(d)/(dt)[2(t-2)]` `=2[1-0]=2 m//s^(2)`

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The displacement of a particle is moving by `x = (t - 2)^2` where `x` is in metres and `t` in second. The distance covered by the particle in first `4` seconds is.A. 4mB. 8mC. 12 mD. 16 m

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