InterviewSolution
Saved Bookmarks
| 1. |
The displacement of a particle moving in straight line is given as function of time as `s = ((t^(3))/(3) - (3t^(2))/(2) + 2t), s` is in m and t is in sec. The particle comes to momentary rest n times Find the value of `n` |
|
Answer» Correct Answer - 2 `s = (t^(3))/(3) - (3t^(2))/(2) + 2t` `:. V = (ds)/(dt) = t^(2) - 3 t + 2` Since the particle comes to rest, therefore, `t^(2) - 3 t + 2 = 0` `(t - 1) (t - 2) = 0` ` t = 1 s " and " 2s` Hence, the particle comes to rest twice. `:. n = 2` |
|