The dissociation constants of two acids `HA_(1)` and `HA_(2)` are `3.0xx10^(-4)` and `1.8xx10^(-5)` respectively. The relative strengths of the acids will be approximatelyA. `1 : 4`B. `4 : 1`C. `1 : 16`D. `16 : 1`

The dissociation constants of two acids `HA_(1)` and `HA_(2)` are `3.0

1.	The dissociation constants of two acids `HA_(1)` and `HA_(2)` are `3.0xx10^(-4)` and `1.8xx10^(-5)` respectively. The relative strengths of the acids will be approximatelyA. `1 : 4`B. `4 : 1`C. `1 : 16`D. `16 : 1`
Answer» Correct Answer - B Relative strength `=sqrt((K_(a_(1)))/(K_(a_(2))))=sqrt((3xx10^(-4))/(1.8xx10^(-5))) implies 4 : 1`

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The dissociation constants of two acids `HA_(1)` and `HA_(2)` are `3.0xx10^(-4)` and `1.8xx10^(-5)` respectively. The relative strengths of the acids will be approximatelyA. `1 : 4`B. `4 : 1`C. `1 : 16`D. `16 : 1`

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