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The distance between the plates of a parallel plate condenser is `4mm` and potential difference is `60` volts. If the distance between the plates is increased to `12mm`, thenA. The potential difference of the condenser will become `180` voltsB. The `P.D.` will become `20` voltsC. The `P.D.` will remain unchangedD. The charge on condenser will reduce to one third |
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Answer» Correct Answer - A For capacitor `(V_(1))/(V_(2)) = (d_(1))/(d_(2)) rArr V_(2) = (V_(1) xx d_(2))/(d_(1)) = (60 xx 12)/(4) = 180 V` |
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