1.

The distance between the points (cos θ, sin θ) and (sin θ, –cos θ) is(a) √3 (b) √2 (c) 1 (d) 0

Answer»

(b) \(\sqrt2\)

Reqd. dist. = \(\sqrt{(sin\,\theta-cos\,\theta)^2+(-cos\,\theta-sin\,\theta)^2}\)

\(\sqrt{(sin\,\theta-cos\,\theta)^2+(-cos\,\theta-sin\,\theta)^2+(cos^2\,\theta+2cos\,\theta\,sin\,\theta+sin^2\,\theta)}\)

\(\sqrt{2(sin^2\,\theta+cos^2\,\theta)}\) = \(\sqrt2\) (∵ cos2 θ + sin2 θ = 1)



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