1.

The distance moved by the screw of a screw gauge is `2 mm` in four rotations and there are `50` divisions on its cap. When nothing is put between its jaws, `20th` divisions of circular scale coincides with reference line, and zero of linear scale is hidden from circular scale when two jaws touch each other or zero circular scale is laying above the reference line. When plate is placed between the jaws, main scale reads `2` divisions and circular scale reads `20` divisions. Thickness of plate is.A. 1.1 mmB. 1.2 mmC. 1.4 mmD. 1.5 mm

Answer» Correct Answer - D
Distance moved in one rotation = `0.5 mm`
Least count, `LC = (0.5 mm)/(50 "divisions")=0.01 mm`
Screw gauge has negative zero error.
This error is `(50 - 20) 0.01 mm` or `(30) (0.01) mm`.
Thickness of plate
= `(2 xx 0.5 mm)+(30 +20)(0.01) mm`
=` 1.5 mm`.


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