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The pitch of a screw gauge is `1 mm` and three are `100` divisions on its circular scale. When nothing is put in between its jaws, the zero of the circular scale lies `6` divisions below the reference line. When a wire a placed between the jaws, `2` linear scale divisions are clearly visible while ` 62` divisions on circular scale coincide with the reference line. Determine the diameter of the wire. |
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Answer» Correct Answer - B `LC = (1 mm)/(100) = 0.01 mm` The instrument has a positive zero error, `e = + n(LC) = +(6 xx 0.01) =0.06 mm` Linear scale reading = `2 xx (1 mm) = 2 mm` Circular scale reading = `62 xx (0.01 mm) = 0.62 mm` `:.` Measured reading = `2 + 0.62 = 2.62 mm` or true reading = `2.62 - 0.06` = `2.56 mm`. |
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