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The distance of a point (2,3) from the line 2x -3y + 9 = 0 measured along a line x-y +1 =0 is : |
Answer» Equation of line 1 x-y+1=0-(1) Equation of line 2 2x-3y+4=0-(2) Subtracting twice equation 1 with equation 2 y+2-9=0 y=7 x=6 Point B(6,7) AB=`sqrt((x_1-x_2)^2+(y_1-y_2)^2)` =`sqrt((6-2)^2+(7-3)^2` =`4sqrt2` Units. |
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