1.

The distance of Neptune and Saturn from the sun is nearly 10^(13)m " and "10^(12)m respectively. Assuming that they move in circular orbits, then what will be the ratio of their time periods.

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SOLUTION :By Kepler's IIIrd law
`((T_n)/(T_s))^2= ((R_n)/(R_s))^3`
`(T_n)/(T_5)= ((R_n)/(R_s))^(3/2)= ((10^(13))/(10^(12)))^(3/2)= 10^(3/2)`
`=10sqrt(10)= 10xx3.16xx31.6`
`T_n : T_s = 36.6 : 1`.


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