Saved Bookmarks
| 1. |
The Distance Of The College And Home Of Rajeev Is 80km. One Day He Was Late By 1 Hour Than The Normal Time To Leave For The College, So He Increased His Speed By 4km/h And Thus He Reached To College At The Normal Time. What Is The Changed (or Increased) Speed Of Rajeev? |
|
Answer» LET the normal speed be x km/h, then 80/x-80/(x+4)=1 ?x2+4x-320=0 ?x (x + 20) - 16 (x + 20) = 0 (x + 20 ) (x - 16) =0 x = 16 km/h Therefore (x + 4) = 20 km/h Therefore INCREASED speed = 20 km/h. Let the normal speed be x km/h, then 80/x-80/(x+4)=1 ?x2+4x-320=0 ?x (x + 20) - 16 (x + 20) = 0 (x + 20 ) (x - 16) =0 x = 16 km/h Therefore (x + 4) = 20 km/h Therefore increased speed = 20 km/h. |
|