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The distance of the point (1,-5,9) from the plane x-y+z = 5 measured along the line x = y = z is |
Answer» `x/1=y/1=z/1` DR(1,1,1) `(x-1)/1=(y+5)/1=(z-9)/1=alpha` `x=alpha+1,y=alpha-5,z=alpha+9` `x-y+z=5` `alpha+1-alpha+5+alpha+4=5` `alpha=5-15=-10` `d=sqrt((-10)^2+(-10)^2+(-10)^2)=10sqrt3`. |
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