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The distance of the point `(2,3)` from the line `x-2y+5=0` measured in a direction parallel to the line `x -3y=0` is:(A) `2sqrt(10)` (B) `sqrt(10)` (C) `2sqrt(5)` (D) None of these |
Answer» x-3y=0 m=1/3 `L_1:y-3=1/3(x-2)` 3y-9=x-2 3y-x=7-(1) x-2y=-5-(2) adding equation 1 and 2 3y-3y=7-5 y=2 x=-1 AB=`sqrt((2-(-1))^2+(3-2)^2)` AB=`sqrt(3^2+1^2)` AB=`sqrt10`. |
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