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The e.m.f. of a cell of negligible internalresistance is 2 V. It is connected to the seriescombination of 2 Ω, 3 Ω and 5 Ω resistances.The potential difference across 3 S2 resistancewill be(A) 0.6 V(C) 3 V(B) 10 V(D) 6 V |
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Answer» total resistance in series = 2+3+5 = 10Ω now current flowing in the circuit is = V/R = 2/10 = 1/5A so, potential difference across 3Ω is = i*r = 3/5v = 0.6v option A |
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