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The effect of TAS on airborne distance is half that of the ideal case.(a) True(b) FalseI have been asked this question during an online exam.This is a very interesting question from Effect on the Take-off Distances of Flight Variables topic in section Take-off and Landing Performance of Aircraft Performance

Answer»

Correct answer is (a) True

The explanation: The effect of TAS on airborne distance is half that of the ideal case. The airborne distance is given by SA=\(\FRAC{W}{(F_N-D)_{AV}}\BIG\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\) where W is weight

D is drag

G is acceleration due to gravity

V is velocity

FN is normal force.



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