The efficiency of a carnot cycle is `1//6` . On decreasing the tempertaure of the sink by `65^(@)C`, the efficiency increases to `1//3` .Calculate the tempretaure of source and sink .

The efficiency of a carnot cycle is `1//6` . On decreasing the tempert

1.	The efficiency of a carnot cycle is `1//6` . On decreasing the tempertaure of the sink by `65^(@)C`, the efficiency increases to `1//3` .Calculate the tempretaure of source and sink .
Answer» Correct Answer - `117^(@)C, 52^(@)` `(1)/(6)=1 - (T_(L))/(T_(H))` `T_(H)=(6)/(5)T_(L)` `(1)/(3)= 1-((T_(L) - 65))/(T_(H))` `T_(L) = 325 K = 52 ^(@)C`

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The efficiency of a carnot cycle is `1//6` . On decreasing the tempertaure of the sink by `65^(@)C`, the efficiency increases to `1//3` .Calculate the tempretaure of source and sink .

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