The efficiency of the Carnot engine is 25% when the temperature of sin

1.	The efficiency of the Carnot engine is 25% when the temperature of sink is 27C. Then temperature of source is:
Answer» \(\eta = 1 - \frac{T_2}{T_1}\) \(\frac{25}{100} = 1 - \frac{300}{T_1}\) \(\frac14 = 1- \frac{300}{T_1}\) \(\frac{300}{T_1} = \frac34\) \(T_2 = \frac{300\times4}{3}\) \(T_1 = 400 K° \) \(T_1 = 127°C\)

The efficiency of the Carnot engine is 25% when the temperature of sink is 27C. Then temperature of source is:

Answer»

\(\eta = 1 - \frac{T_2}{T_1}\)

\(\frac{25}{100} = 1 - \frac{300}{T_1}\)

\(\frac14 = 1- \frac{300}{T_1}\)

\(\frac{300}{T_1} = \frac34\)

\(T_2 = \frac{300\times4}{3}\)

\(T_1 = 400 K° \)

\(T_1 = 127°C\)

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The efficiency of the Carnot engine is 25% when the temperature of sink is 27C. Then temperature of source is:

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