InterviewSolution
Saved Bookmarks
| 1. |
The electric field associated with a light wave is given by `E= E_0 sin [(1.57x 10^7 m^(-1)(x-ct)].` Find the stopping potential when this light is used in an experiment on photoelectric affect with a metal having work - function 1.9 eV. |
|
Answer» Correct Answer - A::B ` f = (omega)/(2pi) = (1.57xx10^7)_c)/(2pi)` `E = (hf)/(1.6xx10^(-19) eV` `=((6.63xx10^(-34)(1.57xx10^7)(3xx10^8)/(1.6xx10^(-19)xx2xxpi)` =3.1 eV `K_(max) = E -W = 1.2 eV.` |
|