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The electron energy in hydrogen atom is given by `E_(n)=(-2.18xx10^(-18))//n^(2)J`. Calculate the energy required to remove an electron completely from the `n=2` orbit. What is the longest wavelength of light in cm that can be used to cause this transition? |
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Answer» Correct Answer - `5.425xx10^(-12)ergs, 3.7xx10^(-5)cm` `E_(n)=(-21.7xx10^(-12))/(n^(2)) 1 erg =10^(-7)` Joule `E_(n)=(-21.7xx10^(-12))/(4)` `J.E.=0-[(-21.7xx10^(-12))/(4)]=(21.7xx10^(-12))/(4)` `=5.425xx10^(-12)` ergs (b) `5.425xx10^(-12)=(6.624xx10^(-34)xx10^(8))/(lambda)` `lambda=(6.624xx3xx10^(8)xx10^(12))/(5.425xx10^(34))=3.7xx10^(-14)(nm)` `3.7xx10^(-14)xx10^(9)cm=3.7xx10^(-5)cm` |
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