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The empirical formula of a non-electrolyte is `CH_(2)O`. A solution containing 3 g `L^(-1)` of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution. The molecular formula of the compound is :A. `CH_(2)O`B. `C_(2)H_(4)O_(2)`C. `C_(4)H_(8)O_(4)`D. `C_(3)H_(6)O_(3)` |
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Answer» Correct Answer - B Concentration of compouinds in solution `= 3g L^(-) = (3)/(M) mol L^(-1)` Since it is isotonic with `0.015M` glucose solution `(3)/(M) = 0.05` or `M = 60` Empirical formula mass of `CH_(2)O = 30` `n = ("Mol .mass")/(EF"mass") = (60)/(30) = 2` `:.` molecular formula `= 2 xx CH_(2)O = C_(2)H_(4)O_(2)` |
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