InterviewSolution
Saved Bookmarks
| 1. |
The energies of activation for forward and reverse reactions for `A_(2) + B_(2) hArr 2AB ` are `180 kJ mol^(-1)` and 200 `kJ mol^(-1)` respectively . The presents of catalyst lowers the activation energy of the both (forward and reverse ) reactions by `100 kJ mol^(-1)` . The enthalpy change of the reaction `(A_(2) + B_(2) to 2AB)` in the presence of catalyst will be (in kJ `mol^(-1)`)A. 300B. 120C. 280D. 20 |
|
Answer» Correct Answer - d So , `DeltaH_("Reaction") = E_(f) - E_(b) = 80 - 100 = -20` . |
|