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The enthalpy change involved in the oxidation of glucoseis `- 2880 kJ mol^(-1)` . Twenty five per cent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk one kilometer, what is the maximum distance that aperson will beableto work after eating 120 g of glucose ? |
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Answer» Energy available for muscular work`=( 25)/( 100) xx 2880 kJ mol^(-1) = 720 kJ mol^(-1)` Molar mass of glucose`= 180 g mol^(-1)` `:. `Energy availablefor muscular work from 120 g glucose `= ( 720 )/( 180) xx120 kJ = 480 kJ` In 100 kJ of muscular work, distance walked `= 1` km `:. ` In 480kJ of muscular work, distance walked `= ( 1)/( 100) xx 480 = 4.8 km` |
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