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The enthalpy of vaporisation of liquid water using the data `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),DeltaH=-285.77kJ//mol` `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g),DeltaH=-241.84kJ//mol` isA. `+43.93kJ//mol`B. `-43.93kJ//mol`C. `527.61kJ//mol`D. `-527.61kJ//mol` |
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Answer» Correct Answer - A (I) `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),DeltaH=-285.77kJ//mol` (II) `H_(2)(g)+(1)/(2)O_(2)(g) to H_(2)O(g),DeltaH=-241.84kJ//mol` `H_(2)O(l)toH_(2)O(g),dDeltaH=?` Subtracting the Eqs. (I) from (II), we get `H_(2)O(l)toH_(2)O(g)` `DeltaH=-241.84-(-285.77)` `DeltaH=+43.93kJ//mol` |
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