The enthalpy of vapourisation of liquid water using the data : `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l) , Delta =-285.77 KJ mol^(-1)` `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(g) , Delta H=-241.84 KJ mol^(-1)`A. `+43.93` KJ `mol^(-1)`B. `-43.93` KJ `mol^(-1)`C. `+527.61` KJ `mol^(-1)`D. `-527.61` KJ `mol^(-1)`

The enthalpy of vapourisation of liquid water using the data : `H_(2)(

1.	The enthalpy of vapourisation of liquid water using the data : `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l) , Delta =-285.77 KJ mol^(-1)` `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(g) , Delta H=-241.84 KJ mol^(-1)`A. `+43.93` KJ `mol^(-1)`B. `-43.93` KJ `mol^(-1)`C. `+527.61` KJ `mol^(-1)`D. `-527.61` KJ `mol^(-1)`
Answer» Correct Answer - A `H_(2)O_((l))rarr H_(2)O_((g)) , Delta H_("Vap.")= ?` Desired equation = eq(ii) - eq(i) `Delta H_("Vap.") =(-241.84)-(-285.77)` `Delta H_("Vap.")=+43.93 KJ mol^(-1)`

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The enthalpy of vapourisation of liquid water using the data : `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l) , Delta =-285.77 KJ mol^(-1)` `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(g) , Delta H=-241.84 KJ mol^(-1)`A. `+43.93` KJ `mol^(-1)`B. `-43.93` KJ `mol^(-1)`C. `+527.61` KJ `mol^(-1)`D. `-527.61` KJ `mol^(-1)`

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