The entropy change can be calculated by using the expression, `DeltaS=(q_("rev"))/(T)`. When water freezes in a glass beaker, choose the correct statement amongst the following:A. `DeltaS_("system")` decreases but `DeltaS_("surroundings")` remains the same.B. `DeltaS_("system")` increases but `DeltaS_("surroundings")` decreases.C. `DeltaS_("system")` decrease but `DeltaS_("surroundings")` increases.D. `DeltaS_("system")` decreases and `DeltaS_("surroundings")` also decreases.

The entropy change can be calculated by using the expression, `DeltaS=

1.	The entropy change can be calculated by using the expression, `DeltaS=(q_("rev"))/(T)`. When water freezes in a glass beaker, choose the correct statement amongst the following:A. `DeltaS_("system")` decreases but `DeltaS_("surroundings")` remains the same.B. `DeltaS_("system")` increases but `DeltaS_("surroundings")` decreases.C. `DeltaS_("system")` decrease but `DeltaS_("surroundings")` increases.D. `DeltaS_("system")` decreases and `DeltaS_("surroundings")` also decreases.
Answer» Correct Answer - C As water freezes from liquid to solid, randomness decreases, i.e., `DeltaS_("system")` decreases. Heat released during the process, is absorbed by the surroundings hence, `DeltaS_("surroundings")` increases.

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