The entropy change can be calculated by using the expression `DeltaS-(q_(rev))/(T)`. When water freezes in a glass beaker, choose the correct statement amongst the following:A. `Delta S` (system) decreases but `Delta S` (surroundings) remains the sameB. `Delta S` (system) increases but `Delta S` (surroundings) decreasesC. `Delta S` (system) decreases but `Delta S` (surroundings) increasesD. `Delta S` (system) decreases but `Delta S` (surroundings) also decreases

The entropy change can be calculated by using the expression `DeltaS-(

1.	The entropy change can be calculated by using the expression `DeltaS-(q_(rev))/(T)`. When water freezes in a glass beaker, choose the correct statement amongst the following:A. `Delta S` (system) decreases but `Delta S` (surroundings) remains the sameB. `Delta S` (system) increases but `Delta S` (surroundings) decreasesC. `Delta S` (system) decreases but `Delta S` (surroundings) increasesD. `Delta S` (system) decreases but `Delta S` (surroundings) also decreases
Answer» Correct Answer - C The entropy change can be calculated by using the expression `Delta S = (q_("rev"))/(T)` When water freezes in a glass beaker, `Delta S` (system) decreases because molecules in solid ice are less random than in liquid water, However, when water freezes to ice, heat. Hence, entropy of the surrounding increases

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