1.

The equation `(cosp - 1) x^2 +cosp x + sinp = 0` where x is a variable, has real roots. then the interval of p may be any one of the following :

Answer» `D>=0`
`b^2-4ac>=0`
`cos^2P-4(cosP-1)sinP>=0`
`c^2P>=4(cosP-1)sinP`
`0<=cos^2P<=1`
`sinP>=0`
`P in[0,pi]`
`(-1/sqrt2)^2>=4(-1/sqrt2=1)-1/sqrt2`
`1/2>=40(1+sqrt2)/(sqrt2-sqrt2)=2(1+sqrt2)`
`1/2<=2(1+sqrt2)`
`P=3/4pi` is not possible.
`P=-pi/4` is not possibble.
option 4 is correct.


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