InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The equation of a circle whose end points of one of its diameter are (2, -3) and (0, 1) is:1. x2 - 2x + y2 + 2y - 3 = 02. x2 + 2x + y2 - 2y - 3 = 03. x2 - 2x + y2 + 2y + 3 = 04. x2 - 2x + y2 + 2y - 5 = 0 |
|
Answer» Correct Answer - Option 1 : x2 - 2x + y2 + 2y - 3 = 0 Concept: The equation of a circle with center at O(a, b) and radius r, is given by: (x - a)2 + (y - b)2 = r2.
Calculation: The co-ordinates of the center of the circle are \(\rm O\left(\frac{2+0}{2},\frac{-3+1}{2}\right)\) = O(1, -1). Radius of the circle = Distance between (0, 1) and (1, -1) = \(\rm \sqrt{(0-1)^2+(1+1)^2}\) = √5. Equation of the circle = (x - 1)2 + (y +1)2 = (√5)2. ⇒ x2 - 2x + y2 + 2y - 3 = 0. |
|