1.

The equation of a transverse wave traveling in a rope is given by txy ),( =10 sin[π 01.0( x − 00.2 t ],) where y and x are expressed in centimeters and t in seconds. (a) Find the amplitude, frequency, velocity, and wavelength of the wave. (b) Find the maximum transverse speed of a particle in the rope.

Answer»

Answer:

The GIVEN EQUATION is y=10sinπ(0.01πx−2πt)

Hence ω= coefficient of t=2π

⇒ maximum SPEED of the PARTICLE vmax=aω=10×2π

=10×2×3.14=62.8=63m/sec

Explanation:



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