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The equation of stationary wave along a stretched string is given by `y=5 sin ((pix)/(3)) cos 40 pi t `, where x and y are in cm and t in second. The separation between two adjacent nodes isA. 6 cmB. 4 cmC. 3 cmD. `1.5` cm |
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Answer» Correct Answer - c The standad equation of statonary wave is `y=2 A sin kx. Cos omegat` …(i) where, a is amplitude, `lambda` is wavelength. Given, `y=5sin frac{pix}{3} cos 40 pit` ...(ii) Comparing Eqs. (i) with (ii), we get `k=pi/3 rArr (2pi)/lambda = pi/3 [because lambda=3 cm]` Distance between adjacent nodes `lambda/2=6/2=3` cm `therefore lambda/2 = 3` cm |
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