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The equation of tangent to the curve given by ` x = 3 cos theta , y = 3 sin theta , at theta = (pi)/(4)` isA. `x + y = sqrt2`B. `3x + y = 3sqrt2`C. `x + y = 3sqrt2`D. ` x + 3y = 3sqrt2` |
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Answer» Correct Answer - C Given x = 3` cos theta , y = sin theta` . On squaring and adding we get `x^(2) + y^(2) = 9` , which represent a circle . `therefore` Equation of tangent at `theta = (pi)/(4)` is `x * (3 cos""(pi)/(4)) + y * (3 sin ""(pi)/(4)) = 9` `implies x + y = 3sqrt2` |
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