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The equation of the line having slope 1 and passing through (3, 2) is A) x + y = 1 B) x – y = 1 C) 2x – y + 1 = 0 D) x – 2y + 1 = 0 |
Answer» Correct option is (B) x – y = 1 Given that slope of required line is m = 1 & it passes through point (3, 2). Let equation of the required line is \(y=mx+c\) \(\Rightarrow\) \(y=x+c\) \((\because m=1)\) Put x = 3 & y = 2 \((\because\) Required line passes through (3, 2)) \(\therefore2=3+c\) \(\Rightarrow c=2-3=-1\) Put c = -1 in \(y=x+c,\) we get \(y=x-1\) \(\Rightarrow x-y=1\) Hence, the equation of required line is \(x-y=1.\) Correct option is B) x – y = 1 |
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