1.

The equation of the normal to the curve `y = sin x` at `(0,0)` isA. `x=0`B. `y=0`C. `x+y=0`D. `x-y=0`

Answer» Correct Answer - C
We have,
`y=sinx rArr (dy)/(dx) = cosx rArr ((dy)/(dx))_((0","0))=cos0=1`
So, the equation of the normal at (0, 0), is
`y-0=(1)/(1)(x-0) rArr y+x=0`


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