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The equation of the normal to the curve `y = sin x` at `(0,0)` isA. `x=0`B. `y=0`C. `x+y=0`D. `x-y=0` |
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Answer» Correct Answer - C We have, `y=sinx rArr (dy)/(dx) = cosx rArr ((dy)/(dx))_((0","0))=cos0=1` So, the equation of the normal at (0, 0), is `y-0=(1)/(1)(x-0) rArr y+x=0` |
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