1.

The equation of the normal to the curve `y=x(2-x)` at the point (2, 0) isA. `x-2y=2`B. `x-2y+2=0`C. `2x+y=4`D. `2x+y-4=0`

Answer» Correct Answer - A
The equation of the curve is `y=x(2-x) or, y=2x-x^(2)`
`rArr (dy)/(dx)=2-2x rArr ((dy)/(dx))_((2","0)) = 2-2 xx2 = -2`
So, the equation of the normal at (2, 0) is
`y-0= -(1)/(-2) (x-2) or, 2y=x-2`


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