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The equation of the plane which passes through (2,-3,1) and is normal to the line joining the points (3,4,-1) and (2,-1,5) is given byA. `x + 5y - 6z + 19 =0`B. `x - 5y + 6z - 19 = 0 `C. `x + 5y + 6z + 19 = 0`D. `x - 5y - 6z - 19 = 0` |
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Answer» Correct Answer - A The equation of plane is `(x - 2) + 5(y + 3) - 6(z-1) = 0` `implies x + 5y - 6z + 19 = 0` |
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