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The equilibrium constannt of a reaction is 0.008 at 298 K. the standard energy change of the reaction at the same temperature isA. `-11.96kJ`B. `-5.43kJ`C. `-8.46kJ`D. `+11.96kJ` |
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Answer» Correct Answer - D Standard free energy change, `DeltaG^(@)=-2.303RTlogK_(c)` `=-2.303xx8.314xx298xxlog` 0.008 `=+11965.16J=11.96kJ` |
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