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The equilibrium constant for a reaction is 10. what will be the value of `DeltaG^(@)`? Given, `R=8.314JK^(-1)mol^(-1),T=300K`.A. `-574.414Jmol^(-1)`B. `-5744.14Jmol^(-1)`C. `-57.4414Jmol^(-1)`D. `57441.4Jmol^(-1)` |
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Answer» Correct Answer - B `DeltaG^(2)=-2.303RTlogK_(c)` `DeltaG^(@)=-2.303xx8.314JK^(-1)mol^(-1)xx300Kxxlog10` `=-5744.14J" "mol^(-1)`. |
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