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The equilibrium constant for a reaction is `10`. What will be the value of `DeltaG^(Θ)`? `R=8.314 J K^(-1) mol^(-1), T=300 K`. |
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Answer» From the expression, `DeltaG^(theta)=-2.303RT "log"K_(eq)` `DeltaG^(theta)` for the reaction, `=(2.303)(8.314 JK^(-1)"mol"^(-1)) (300K)` log10 `-5744.14 J"mol"^(-1)` `-5.744 kJ "mol"^(-1)` |
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