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The equilibrium constant for a reaction is 10.What will be thevalue of `DeltaG^(@) ` ? ` R=8.314 JK^(-1)mol^(-1) , T = 300 K `.

Answer» `DeltaG^(@) =-2.303 RT log K=-2.303 xx 8.314 JK^(-1) JK^(-1) mol^(-1) xx300 K xxlog10 = -5744.1 J`


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