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The exess pressure inside a drop of soap solution is Pd and that inside a soap bubble of same radius is` P_(d)` thenA. `P_(d)=P_(b)`B. `P_(b)=2P_(d)`C. `P_(d)=2P_(b)`D. `P_(b)=4P_(d)` |
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Answer» Correct Answer - B ` P_(d) = (2T)/r` `P_(b) = (4T)/r ` ` (P_(b))/(P_(d))= (4T)/r xx r/(2T) = 2 ` ` P_(b)=2P_(d)` |
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