InterviewSolution
Saved Bookmarks
| 1. |
The explosion of a fire cracker in the air at the a heigth of `40 m` produced a `100 dB` sound level at ground below. What is the instantaneous total radiated power? Assuming that it radiates as a point source. |
|
Answer» Correct Answer - A::B `l_(1) = 10 log_(10) ((I)/(I_(o)))` `100 = 10 log_(10) ((I)/(10^(-12)))` Solving we get, `I = 10^(-2) W//m^(2)` Now, `I = (P)/(4pi r ^(2))` :. `P = I (4 pi r^(2))` = `(10^(-2)) (4 pi) (40)^(2)` = `201 W` |
|