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The expression for the loss tangent is given by(a) σ/ωε(b) ωε/σ(c) σ/ω(d) ω/εI got this question in class test.I'm obligated to ask this question of Loss Tangent in chapter Maxwell Equations of Electromagnetic Theory

Answer»

Right option is (a) σ/ωε

To elaborate: The CONDUCTION current DENSITY is Jc = σ E and the displacement current density is Jd = jωεE. Its magnitude will be ωεE. Thus the LOSS TANGENT TAN δ = Jc /Jd = σ/ωε is the required expression.



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