The figure shown, the p-V diagram of two different masses `m_(1) and m_(2)` drawn at constant temperature T, then ltbr. A. `m_(1)gtm_(2)`B. `m_(2)gtm_(1)`C. `m_(1)=m_(2)`D. insufficient data

The figure shown, the p-V diagram of two different masses `m_(1) and m

1.	The figure shown, the p-V diagram of two different masses `m_(1) and m_(2)` drawn at constant temperature T, then ltbr. A. `m_(1)gtm_(2)`B. `m_(2)gtm_(1)`C. `m_(1)=m_(2)`D. insufficient data
Answer» Correct Answer - B We know that, `pV =nRT=(m)/(M)RT` `m=(pV)(M)/(RT)` m`prop`pv `p_(2)V_(2)gtP_(1)V_(1)` From the curve, `m_(2)gtm_(1)`

Discussion

No Comment Found

Related InterviewSolutions

In a crude model of a rotating diatomic molecule of chlorine `(Cl_2)`, the two `(C l)` atoms are `2.0 xx 10^-10 m` apart and rotate about their centre of mass with angular speed `omega = 2.0 xx 10^12 "rad" //s`. What is the rotational kinetic energy of one molecule of `C l_(2)` , Which has a molar mass of `70.0 g // mol` ? .A. `2.32xx10^(-20)J`B. `2.32xx10^(-21)J`C. `2.32xx10^(-19)J`D. `2.32xx10^(-22)J`
Four molecules of ags have speeds 1,2,3 and 4 `km//s`.The volue of the root mean square speed of the gas molecules isA. `(1)/(2)sqrt(15)km//s`B. `(1)/(2)sqrt(10)km//s`C. `2.56 km//s`D. `sqrt(15/2)km//s`
The average kinetic energy of gas molecule at `27^(@)C` is `6.21xx10^(-21)` J. Its average kinetic energy at `127^(@)C` will beA. `12.2xx10^(-21)J`B. `8.28xx10^(-21)J`C. `10.35xx10^(-21)J`D. `11.35xx10^(-21)J`
For gas at a temperature `T` the root-mean-square speed `v_(rms)`, the most probable speed `v_(mp)`, and the average speed `v_(av)` obey the relationshipA. `V_(mp)gtV_(av)gtV_(ms)`B. `V_(ms)gtV_(av)gtV_(mp)`C. `V_(av)gtV_(mp)gtV_(ms)`D. `V_(mp)gtV_(ms)gtV_(av)`
12 g of gas occupy a volume of `4xx10^(-3) m^(3)` at a temperature of `76^(@)C`.after the gas is heated at constant pressure, its density becomes `6xx10^(-4) g//cm^(3)`.What is the temperature to which the gas was heated?A. 1000 KB. 1400 KC. 1200 KD. 800 K
A vessel contains a mixture of nitrogen of mass 7 g and carbon dioxide of mass 11 g at temperature 290 K and perssure 1 atm.Find the density of the mixture.A. `1.1 g//L`B. `1.2 g//L`C. `1.515 g//L`D. `1.6 g//L`
One litre of oxygen at a pressure of 1 atm and two litres of nitrogen at a pressure of 0.5 atm are introduced into a vessel of volume 1 litre. If there is no change in temperature, the final pressure of the mixture of gas (in atm) isA. 1.5B. 2.5C. 2D. 4
Two perifect gases at absolute temperatures `T_(1) and T_(2)` are mixed. The absolute temperature of the mixture is T. there is no loss of energy.If `m_(1) and m_(2)` are masses of molecules and `n_(1) and n_(2)` are number of molecules, thenA. `T=(T_(1)+T_(2))/(2)`B. `T=(n_(1)T_(1)+n_(2)T_(2))/(n_(1)+n_(2))`C. `T=(n_(1)T_(1)+n_(2)T_(2))/(T_(1)+T_(2))`D. None of the above
How many cylinders of hydrogen at atmospheric pressure are required to fill a ballon whose volume is `500 m6(3)` if hydrogen is stored in cylinders of volume 0.05 `m^(3)` at an absolute presure of `15xx10^(5)` Pa?A. 700B. 675C. 605D. 710
Figure shows graphs of pressure vs density for an ideal gas at two temperature `T_(1) and T_(2)`. Which of the following is correct? A. `T_(1)gtT_(2)`B. `T_(1)=T_(2)`C. `T_(1)ltT_(2)`D. any three is possible

The figure shown, the p-V diagram of two different masses `m_(1) and m_(2)` drawn at constant temperature T, then ltbr. A. `m_(1)gtm_(2)`B. `m_(2)gtm_(1)`C. `m_(1)=m_(2)`D. insufficient data

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment