The first four terms of an AP, whose first term is –2 and the common

1.	The first four terms of an AP, whose first term is –2 and the common difference is –2, are(A) – 2, 0, 2, 4(B) – 2, 4, – 8, 16(C) – 2, – 4, – 6, – 8(D) – 2, – 4, – 8, –16
Answer» (C) – 2, – 4, – 6, – 8 Explanation: First term, a = – 2 Second Term, d = – 2 a_{1 =} a = – 2 We know that the nth term of an AP is a_{n =} a + (n – 1)d Where, a = first term a_n is nth term d is the common difference Hence, we have, a_{2 =} a + d = – 2 + (- 2) = – 4 Similarly, a_{3 =} – 6 a_{4 =} – 8 So the A.P is – 2, – 4, – 6, – 8

The first four terms of an AP, whose first term is –2 and the common difference is –2, are(A) – 2, 0, 2, 4(B) – 2, 4, – 8, 16(C) – 2, – 4, – 6, – 8(D) – 2, – 4, – 8, –16

Answer»

(C) – 2, – 4, – 6, – 8

Explanation:

First term, a = – 2

Second Term, d = – 2

a_{1 =} a = – 2

We know that the nth term of an AP is

a_{n =} a + (n – 1)d

Where,

a = first term

a_n is nth term

d is the common difference

Hence, we have,

a_{2 =} a + d = – 2 + (- 2) = – 4

Similarly,

a_{3 =} – 6

a_{4 =} – 8

So the A.P is

– 2, – 4, – 6, – 8