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The first law of thermodynamics for a closed system is dU = dq + dw, where dw = `dw_(pv)+dw_("non-pv")`. The most common type of `w_("non-pv")` is electrical work. As per IUPAC convention work done on the system is positive. A system generates 50 J electrical energy, has 150 J of pressure-volume work done on it by the surroundings while releasing 300 J of heat energy. What is the change in the internal energy of the sytem?A. `-500`B. `-100`C. `-300`D. `-200`

Answer» Correct Answer - D
`DeltaU=q+w`
`DeltaU=-300+(-50+150)=-200`


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