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The first order rate constant for the decomposition of `N_(2)O_(5)` is `6.2 xx 10^(-4) sec^(-1)`. The `t_(1//2)` of decomposition isA. `1117.7`B. `111.7`C. `223.4`D. `160` |
Answer» Correct Answer - a `t_(1//2) = (0.693)/(k) = (0.693)/(6.2 xx 10^(-4)) = 1117.7 ` sec . |
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