The first overtone frequency of a closed organ pipe `P_1` is equal to the fundamental frequency of an open organ pipe `P_2`. If the length of the pipe `P_1` is 30 cm, what will be the length of` P_2`?

The first overtone frequency of a closed organ pipe `P_1` is equal to

1.	The first overtone frequency of a closed organ pipe `P_1` is equal to the fundamental frequency of an open organ pipe `P_2`. If the length of the pipe `P_1` is 30 cm, what will be the length of` P_2`?
Answer» Correct Answer - B::C According to the questions `f_1` first overtone of a closed organn pipe `P_1=(3v)/(4I)=((3xxV)/(4xx30)) `=f_2=` fundamental frequency of a open organ pipe `P_2=(V/(2I_2))` `Here given ((3xxV)/(4xx30))=V/(2I_2)` `rarr I_2=20cm` `:. length of the pipe `P_2` will be 20 cm.

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The first overtone frequency of a closed organ pipe `P_1` is equal to the fundamental frequency of an open organ pipe `P_2`. If the length of the pipe `P_1` is 30 cm, what will be the length of` P_2`?

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