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The first term of an A.P. is 5 and its 100th term is -292. Find the 50th term of this A.P. |
Answer» Given, an A.P whose a = 5 and a100 = -292 We know that an = a + (n – 1)d a100 = 5 + 99d = -292 99d = -297 d = -3 Hence, the 50th term is a50 = a + 49d = 5 + 49(-3) = 5 – 147 = -142 |
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