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The first term of an A.P. is 5 and its 100th term is - 292. Find the 50th term of this A.P. |
Answer» Given, a = 5 a100 = - 292 5 – 99d = - 292 d = \(\frac{-297}{-99}\) = 3 Now, 50th term, a50 = a + (50 – 1) d = 5 + (49) 3 = 5 + 147 = 152 Hence, 50th term of given A.P. is 152 |
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