InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The flow of blood in a large artery of an anaeshetized dog is diverted throg]ugh a venturimeter. The wider part of the meter has a cross sectional area equal to that of the artery i.e. `8 mm^(2)`. The narrower parts has an are `4 mm^(2)`. The pressure dorp in the artery is `24Pa`. what is the speed of the blood in the artery ? Given that density of the blood = `1.06 xx 10^(3) kg//m^(3)` |
|
Answer» Here, `a_(1) = 8 mm^(2) = 8 xx 10^(-6)m^(2)`, `a_(2) = 4mm^(2) = 4 xx 10^(-6) m^(2)` `P_(1) - P_(2) = 24 Pa, rho = 1.06 xx 10^(3) kg//m^(3)` `upsilon = V/(a_(1)) = a_(2) sqrt((2(P_(1)-P_(2)))/(rho(a_(1)^(2)-a_(2)^(2))))` `= 4 xx 10^(-6)` ` xx [(2 xx 24)/((1.06 xx 10^(3))[(8xx10^(-6))^(2)-(4 xx 10^(-6))^(2)])]^(1//2)` `= 0.123 ms^(-1)` . |
|